Re: Why does calling readln() more than once not work

[Adam D. Ruppe via Digitalmars-d-learn]

On Thursday, 28 January 2021 at 19:25:52 UTC, Ruby The Roobster 
wrote:
        readf(" %d",&tempy);

This leaves the \n at the end. A next readf thanks to the leading 
space would ignore that \n and keep going, but a readln stops at 
the first \n it sees, even if it is a leftover item in the buffer 
from a readf before.