On Thursday, 28 January 2021 at 19:31:35 UTC, Adam D. Ruppe wrote:
On Thursday, 28 January 2021 at 19:25:52 UTC, Ruby The Roobster
wrote:
readf(" %d",&tempy);
This leaves the \n at the end. A next readf thanks to the
leading space would ignore that \n and keep going, but a readln
stops at the first \n it sees, even if it is a leftover item in
the buffer from a readf before.
I replaced readln with the following: readf(" %s\n",&tempz);
That seemed to do the trick(and note here, when you press enter,
it stops taking input).
