On Saturday, 3 April 2021 at 13:50:27 UTC, ag0aep6g wrote:
On 03.04.21 15:34, DLearner wrote:
The following produces the expected result.
However, changing extern(C) to extern(D) causes linker
failures.
To me, that is bizarre.
Testmain:
extern(C) int xvar;
[...]
Testmod:
extern extern(C) int xvar;
With `extern (C)`, those two `xvar`s refer to the same data.
Without `extern (C)` (or with `extern (D)`), they are distinct
variables with no relation to another. In D, you don't
re-declare another module's symbols. You import the other
module.
----
module testmain;
import std.stdio: writeln;
import testmod: testsub, xvar;
void main()
{
xvar = 1;
writeln(xvar); /* prints "1" */
testsub();
writeln(xvar); /* prints "2" */
}
----
----
module testmod;
int xvar; /* same as `extern (D) int xvar;` */
void testsub()
{
xvar = 2;
}
----
Thank you, your suggestions worked.
No externs anywhere.
For the record, the code is below.
import itf;
import testmod:testsub;
void main() {
import std.stdio;
writeln("Entering: main");
xvar = 1;
writeln("xvar=", xvar);
testsub();
writeln("xvar=", xvar);
writeln("Leaving: main");
}
module itf;
int xvar;
module testmod;
import itf;
void testsub() {
import std.stdio;
writeln("Entering: testsub");
writeln("xvar=", xvar);
xvar = 2;
writeln("xvar=", xvar);
writeln("Leaving: testsub");
}