On Sunday, 16 May 2021 at 20:32:08 UTC, SealabJaster wrote:
...

You could even make a helper function that lets the compiler infer the lambda's type for you:

```d
struct S(T)
{
   alias FT = T function(T);
   FT func;
}

S!T s(T)(T function(T) func)
{
    return S!T(func);
}

void main()
{
    auto a = S!int(a => a*2);
    auto b = s((int a) => a+2);
    a = b;
}
```

But that can give you awful looking error messages if you forget to add the param typing.

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