On Tuesday, 10 May 2022 at 04:30:28 UTC, Ali Çehreli wrote:
I just found something that looked like a workaround. I don't know whether it is by design or by accident or whether this exercise exposes a compiler or language bug. Sorry... :)
I can't exactly use the is(T == char) or is(T : char) check. It isn't happening! But I still have a little more patience :)
SDB@79
