On Friday, 1 December 2023 at 01:01:31 UTC, Siarhei Siamashka
wrote:
Advent of Code 2023 starts in a few hours from now. I suggest
to discuss D language solutions here.
But to avoid spoilers, it's best to do this with a 24h delay
after each puzzle is published.
Day 1 solution
```d
version = Part2;
import std.stdio;
import std.algorithm;
import std.array;
import std.format;
import std.conv;
import std.string;
int[string] numberMap;
static this() {
numberMap = [
"one": 1,
"two": 2,
"three": 3,
"four": 4,
"five": 5,
"six": 6,
"seven": 7,
"eight": 8,
"nine": 9
];
}
int findNum(T)(T /*char[] and string; since example and file read
are different*/ str, bool reverse) {
for(size_t i = reverse ? str.length - 1: 0; reverse ? i >= 0 : i
< str.length; i += (reverse ? -1 : 1)) {
auto c = str[i];
if(c >= '0' && c <= '9')
return to!int(c - '0');
version(Part2) {
foreach(key, value; numberMap) {
if(key.length > str.length - i)
continue;
if(str[i..i+key.length] == key) {
return value;
}
}
}
}
writeln(str, " ", reverse);
assert(false);
}
int main() {
File("input")
.byLine
/*[
"two1nine",
"eightwothree",
"abcone2threexyz",
"xtwone3four",
"4nineeightseven2",
"zoneight234",
"7pqrstsixteen"
]*/
.map!((str) {
auto firstNum = findNum(str, false);
auto secNum = findNum(str, true);
auto code = firstNum * 10 + secNum;
return code;
})
.sum
.writeln;
return 0;
}
```
I am a bloody beginner so if there are any things that are very
wrong with this please point them out.
The fact that I need a template for accepting both a string and a
char[] is very weird but I went with it. I am also curious if
there is a better way for the reversible for-loop to happen. I
saw foreach and foreach_reverse but I don't think that helps me
here, since I swap them out based on a runtime argument.
