Re: Generate array of random values

[David Nadlinger]

On 8/2/11 6:42 AM, Jesse Phillips wrote:
     auto arr = new int[1024];
     fill(arr, randomCover(iota(0,1024), rndGen));

Note that this produces a random permutation of the numbers 0 to 1023, 
which may or may not be what you want.

David