On 2012-09-10 01:20, timotheecour wrote:
I'd like to achieve the following:
----
import std.stdio,std.range,std.algorithm,std.array;
void main(){
auto dg=a=>a*2;
auto a=iota(0,10);
writeln(a.map!dg.array);
}
----
but this doesn't compile:
Error: variable [...]dg type void is inferred from initializer delegate
(__T26 a)
{
return a * 2;
}
, and variables cannot be of type void
However this works:
writeln(a.map!(a=>a*2).array);
but I want to reuse dg in other expressions (and avoid repeating myself)
Also, I want to avoid using string litteral enum dg=`a*2` as in my case
dg is much more complicated and this is cleaner without a string IMHO.
My questions:
1) why can't the compiler infer the type int(int) for dg?
2) how to convert a lambda a=>a*2 to a delegate or function?
Try this:
auto dg = (int a) => a * 2;
If that doesn't work, this should:
auto dg = (int a) { return a * 2; };
--
/Jacob Carlborg
