On 03/14/2013 10:45 AM, Andrea Fontana wrote: > You see? Your code do this: > > a[] = (b[] < c[]);
I thought the same thing at first but note the brackets after b and c. Those should make this an array-wise operation.
For all elements of a to be the same value, one would not write the brackets:
a[] = b < c;
Some of the array-wise operations are confusing. :/
Ali
