On Thursday, 14 March 2013 at 17:56:07 UTC, Ali Çehreli wrote:
On 03/14/2013 10:45 AM, Andrea Fontana wrote:
> You see? Your code do this:
>
> a[] = (b[] < c[]);
I thought the same thing at first but note the brackets after b
and c. Those should make this an array-wise operation.
For all elements of a to be the same value, one would not write
the brackets:
a[] = b < c;
Some of the array-wise operations are confusing. :/
Ali
Doesn't a[] means copy of a?
So copyofa[] < copyofb[] == bool
I don't think a boolean operator can be array-wise... I always
think X < Y return a single bool, indipendently from X or Y type
(class, array or what else). Math operations is a different topic
in my mind.
