On Thu, 04 Jul 2013 08:02:13 -0400, monarch_dodra <monarchdo...@gmail.com>
wrote:
This is a pretty stupid question, but how would you allocate an "int[]"
on the heap? I'm not talking about the array, but the actual slice
object. EG:
int[]* pSlice = new int[];
//Error: new can only create structs,
//dynamic arrays or class objects, not int[]'s
Is there a simple "idiomatic" way?
Not really. There was talk at one point of deprecating that version, so
you had to do new int[](5) instead of new int[5], and then using new
int[5] to mean new "fixed sized array of size 5 on the heap", and then new
int[] would mean new slice on the heap.
But I think there's a real lack of benefit to this, plus it would be
confusing to people familiar with other languages.
I'm currently doing it by allocating a struct that wraps one:
struct S{int[] a;}
int[]* pSlice1 = cast(int[]*) new S;
int[]* pSlice2 = &(new S).a;
Note: This is also a neat way to allocate a static array on the heap.
Anybody have some better way?
This should work:
int[] *pSlice = (new int[][1]).ptr;
-Steve
