On Thursday, 4 July 2013 at 13:37:52 UTC, Steven Schveighoffer
wrote:
On Thu, 04 Jul 2013 08:02:13 -0400, monarch_dodra
<monarchdo...@gmail.com> wrote:
This is a pretty stupid question, but how would you allocate
an "int[]" on the heap? I'm not talking about the array, but
the actual slice object. EG:
int[]* pSlice = new int[];
//Error: new can only create structs,
//dynamic arrays or class objects, not int[]'s
Is there a simple "idiomatic" way?
Not really. There was talk at one point of deprecating that
version, so you had to do new int[](5) instead of new int[5],
and then using new int[5] to mean new "fixed sized array of
size 5 on the heap", and then new int[] would mean new slice on
the heap.
But I think there's a real lack of benefit to this, plus it
would be confusing to people familiar with other languages.
One advantage I see is that it is a way to allocate a fixed
amount of objects in memory in heap, without having to add the
Appendable info.
But that change would require changing an existing semantic, so
fat chances of that happening now.
I'm currently doing it by allocating a struct that wraps one:
struct S{int[] a;}
int[]* pSlice1 = cast(int[]*) new S;
int[]* pSlice2 = &(new S).a;
Note: This is also a neat way to allocate a static array on
the heap.
Anybody have some better way?
This should work:
int[] *pSlice = (new int[][1]).ptr;
-Steve
Hum... That would allocate a dynamic array of slices though
right? There'd be the Appendable overhead for just one element...
