Joseph Rushton Wakeling:
Suppose that I have an "out" parameter in a function:
int foo(in int i, out int j)
{
j = /* something */;
return /* whatever */;
}
Is there any way to mark that out parameter as optional, i.e.
so that it only gets written to/used if a corresponding
parameter is passed to the function?
One simple solution is to define two overloaded functions, one
with and one without the j argument.
If you want a single function, dropping out you can write:
int foo(size_t N)(in int i, int[N] j...)
if (N < 2) {
static if (N == 1)
j[0] = i;
return i;
}
void main() {
auto r1 = foo(1);
int x;
auto r2 = foo(1, x);
}
Bye,
bearophile
