template operator overload

[Namespace]

Just out of curiosity: Is it possible to call an overloaded 
operator with a template type?
----
import std.stdio;

struct A {
        void opIndex(T)(size_t index) {
                
        }
}
void main() {
        A a;
        a.opIndex!int(0); // [1]
        a!int[0]; // [2]
}
----

[1] works, but [2] fails.
How can I call opIndex with bracket syntax and a typename? Or is 
this not possible?