Re: template operator overload

[Shammah Chancellor]

On 2013-11-27 16:07:50 +0000, Namespace said:

Just out of curiosity: Is it possible to call an overloaded operator 
with a template type?
----
import std.stdio;
struct A {
        void opIndex(T)(size_t index) {
                
        }
}

void main() {
        A a;
        a.opIndex!int(0); // [1]
        a!int[0]; // [2]
}
----

[1] works, but [2] fails.
How can I call opIndex with bracket syntax and a typename? Or is this 
not possible?

You need to simply use template deduction, and cast the parameter to 
what you're wanting to use between the brackets.

a[cast(int)0] (although zero is already an int);