On Thursday, 20 March 2014 at 21:25:03 UTC, Ali Çehreli wrote:
This is a somewhat common little exercise: Write a function
that takes the size of a diamond and produces a diamond of that
size.
When printed, here is the output for size 11:
*
***
*****
*******
*********
***********
*********
*******
*****
***
*
What interesting, boring, efficient, slow, etc. ways are there?
Ali
I'm not entirely happy with it but:
void main()
{
import std.algorithm, std.range, std.stdio, std.conv;
enum length = 5;
auto rng =
chain(iota(length), iota(length, -1, -1))
.map!((a => " ".repeat(length-a)),
(a => "#".repeat(a*2+1)))
.map!(a => chain(a[0].joiner, a[1].joiner, "\n"))
.joiner;
writeln(rng);
}
Had some trouble with the result coming out as integers instead
of something string-like.
