Re: can I overload operators as extension methods?

[Adam D. Ruppe via Digitalmars-d-learn]

On Thursday, 9 March 2017 at 23:50:04 UTC, XavierAP wrote:
The same way as T.foo() is lowered to foo(T) if no such member 
is defined inside the type.

No.

But wrapping in a struct with alias this lets you extend them 
pretty easily too.