On Tuesday, 4 July 2017 at 23:26:28 UTC, H. S. Teoh wrote:
On Tue, Jul 04, 2017 at 11:27:25PM +0000, Jean-Louis Leroy via
Digitalmars-d-learn wrote:
I want to create a range that consists of the result of a map()
followed by a value, e.g.:
int[] x = [ 1, 2, 3];
auto y = map!(x => x * x)(x);
auto z = y ~ 99; // how???
I have tried several variations: convert 99 to a dynamic
array, to a range, convert range to dynamic array (couldn't
even figure that one); to no avail.
[...]
Try:
auto z = chain(y, only(99));
Thanks!
However, when I try to use this construct in my real code, I
still have a problem:
// k is a ClassInfo
chain(map!(i => i.classinfo)(k.interfaces), only(k.base))
meth.d(311): Error: template std.range.chain cannot deduce
function from argument types !()(MapResult!(__lambda3,
Interface[]), OnlyResult!(TypeInfo_Class, 1LU)), candidates are:
/usr/include/d/std/range/package.d(795):
std.range.chain(Ranges...)(Ranges rs) if (Ranges.length > 0 &&
allSatisfy!(isInputRange, staticMap!(Unqual, Ranges)) &&
!is(CommonType!(staticMap!(ElementType, staticMap!(Unqual,
Ranges))) == void))
