On Tuesday, July 04, 2017 23:50:57 Nicholas Wilson via Digitalmars-d-learn wrote: > On Tuesday, 4 July 2017 at 23:27:25 UTC, Jean-Louis Leroy wrote: > > I want to create a range that consists of the result of a map() > > > > followed by a value, e.g.: > > int[] x = [ 1, 2, 3]; > > auto y = map!(x => x * x)(x); > > auto z = y ~ 99; // how??? > > > > I have tried several variations: convert 99 to a dynamic array, > > to a range, convert range to dynamic array (couldn't even > > figure that one); to no avail. > > > > Help please... > > using > auto y = x.map!(x => x * x).array; > will work.
Yeah, that will convert the range to a dynamic array, but if you're looking to do is append onto a range, then using chain like H.S. Teoh showed is better. And even if you ultimately want a dynamic array, using chain and then calling array on the result than allocating the array and then appending to it as an array means that you're only going to allocate the array once, whereas if you append to the array, you might end up causing it to be reallocated (though if you're just appending a single element to it it'll have the space unless in std.array.array allocates a dynamic array with exactly the space required for its elements, which I doubt). - Jonathan M Davis
