On Thursday, 1 March 2018 at 21:31:49 UTC, Steven Schveighoffer
wrote:
No, I think you did int[3][2], if you got that output.
Otherwise it would have been:
[[[0,0,0],[0,0,0]]]
Yes apologies that was there from a previous attempt, you are
correct.
Well, that's because that type of slicing isn't supported
directly. You can't slice an array cross-wise like that.
You may be interested in ndslice inside mir:
http://docs.algorithm.dlang.io/latest/mir_ndslice.html
Thanks I've just had a quick read and this looks promising for
what I want (similar functionality to numpy), but I also want to
understand arrays.
when I try
arr[0 .. 2][0] = 3; // which I think is equivalent to
arr[0][0]
Consider the array:
int[] x = new int[2];
Now, what would the slice x[0 .. 2] be? That's right, the same
as x.
So when you slice arr[0 .. 2], it's basically the same as arr
(as arr has 2 elements).
So arr[0 .. 2][0] is equivalent to arr[0].
So if I do
arr[0 .. 1][0] = 3;
shouldn't this return
[[3, 0, 0], [0, 0, 0]] ? Because I'm taking the slice arr[0
.. 1], or arr[0], which is the first [0, 0, 0]? Then assigning
the first element to 3?
instead it returns
[[3, 3, 3], [0, 0, 0]]
One thing that is interesting is that you assigned 3 to an
array, and it wrote it to all the elements. I did not know you
could do that with static arrays without doing a proper slice
assign. But it does compile (I learn something new every day).
-Steve
Well I'm learning a lot today :)
