On 3/1/18 5:59 PM, ag0aep6g wrote:
On 03/01/2018 11:43 PM, Jamie wrote:
So if I do
arr[0 .. 1][0] = 3;
shouldn't this return
[[3, 0, 0], [0, 0, 0]] ? Because I'm taking the slice arr[0 ..
1], or arr[0], which is the first [0, 0, 0]?
arr[0 .. 1] is not the same as arr[0].
arr[0 .. 1] is not the first element of arr; it's an array that contains
the first element of arr. It's not [0, 0, 0]; it's [[0, 0, 0]]. It's not
an int[]; it's an int[][].
Minor correction, it's actually an int[3][].
Try arr[1 .. 2][0] = 3; It will affect the second static array.
I understand what you really want is the first element of each static
array. There is no supported syntax for arrays to slice like that. This
is where ndslice comes in.
But if it *were* supported, it would look like this instead (I think
this is how ndslice would work, but I've never used it):
arr[0 .. 2, 0] = 3;
The thing I think you are missing is that the expression stops at the
closing bracket.
In other words arr[0 .. 2][0] is really (arr[0 .. 2])[0].
arr[0 .. 2] is a slice of the original array, which happens to be the
entire array. So it really doesn't get you anything.
One final note. If you don't want to use array assignment operators, and
don't mind using ranges, you can do what you want this way:
https://run.dlang.io/is/AdikEE
-Steve
