On Wednesday, 7 November 2018 at 13:05:49 UTC, test wrote:
I am confused about the bitfields order.
mixin(bitfields!(
bool, "fin", 1,
bool, "rsv1", 1,
bool, "rsv2", 1,
bool, "rsv3", 1,
Opcode, "opcode", 4,
bool, "mask", 1,
ubyte, "_size", 7,
));
output for first byte is 10000001 , the 2st byte 10000011
my code output: opcode=8 mask=true size=65
the real size is 3 byte, and opcode is 1;
how to fix this ?
The bitfields start with the least significant bits:
fin -> 1
rsv1 -> 0
rsv2 -> 0
rsv3 -> 0
opcode -> 1000 = 8
mask -> 1
_size -> 1000001 = 65
This order will likely be what you want:
mixin(bitfields!(
opcode, "opcode", 4,
bool, "rsv3", 1,
bool, "rsv2", 1,
bool, "rsv1", 1,
bool, "fin", 1,
ubyte, "_size", 7,
bool, "mask", 1,
));
Also beware of endianness when mapping bytes to it.
