On Wednesday, 7 November 2018 at 14:22:43 UTC, lithium iodate
wrote:
On Wednesday, 7 November 2018 at 13:05:49 UTC, test wrote:
I am confused about the bitfields order.
The bitfields start with the least significant bits:
fin -> 1
rsv1 -> 0
rsv2 -> 0
rsv3 -> 0
opcode -> 1000 = 8
mask -> 1
_size -> 1000001 = 65
This order will likely be what you want:
mixin(bitfields!(
opcode, "opcode", 4,
bool, "rsv3", 1,
bool, "rsv2", 1,
bool, "rsv1", 1,
bool, "fin", 1,
ubyte, "_size", 7,
bool, "mask", 1,
));
Also beware of endianness when mapping bytes to it.
After I use your code it working now.
my other question is: if the opcode bit cross byte, how do we
define the bitfields ?
for example if the opcode is a 6 bit number instead 4bit :
F1|R1|R1|R1|opcode6|Mask1|Size5
I has to split the opcode here ?
mixin(bitfields!(
opcode, "opcode4", 4,
bool, "rsv3", 1,
bool, "rsv2", 1,
bool, "rsv1", 1,
bool, "fin", 1,
ubyte, "_size", 5,
bool, "mask", 1,
bool, "opcode2", 1,
));