On 1/21/19 10:54 AM, Matheus wrote:
On Monday, 21 January 2019 at 15:01:27 UTC, Steven Schveighoffer wrote:
Probably, this optimizes into better code, but maybe the optimizer
already does this with the expression above:
auto tmp = n % 3;
if(tmp < 0)
tmp += 3;
It's just not a nice single expression.
I don't think you can do this, imagine this case:
auto tmp = -1 % -3; // Note divisor in negative too.
tmp will be "-1" which already matches the Python way, so you can't add
If the divisor is unknown, I hadn't considered the case. I was only
considering the case where the divisor is a constant.
In that case, one can probably determine if the divisor is less than 0
Not a Python user, just hoping to help answer questions :)