On Wednesday, 17 April 2019 at 23:44:42 UTC, Adam D. Ruppe wrote:

In C++, if you define a struct/class, and constructors apply for this.

struct Test {
   Test(const char* foo) {}

void cool(Test t) {}

cool("string"); // works

That works in C++, unless you mark that constructor with `explicit`

struct Test {
explicit Test(const char* foo) {} // this opts out of the cool thing above

Yes, thanks. :)

Actually, I asked initially because in C++ you can do the thing I described.
I thought that you meant something I missed with out-out.

- Stefanos

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