04-Feb-2013 19:15, Andrej Mitrovic пишет:
On 2/4/13, kenji hara <[email protected]> wrote:
This is not correct."m.s & m.s" is always parsed as binary bitwise AND
expression.
So there is no address expression.
Fantastic, more special casing. I don't think you guys realize what a
mess you would introduce. Basically:
s & s; // fine, they're binary operators
&s; // oops, doesn't work even if property returns a type with a unary operator
Unary & is not overloadable, precisely due to confusing mess it can
create (see C++).
--
Dmitry Olshansky
