On Friday, 22 February 2013 at 18:55:58 UTC, kenji hara wrote:
No, const/inout overload does not intend to solve 'method
hiding' problem.
To clarify the situation, I try to explain.
class A {
void foo() {}
void foo() const {}
}
You missed the important part. I'm talking about overload, not override. IE, not method hiding.
What you have in class A here is useful for use cases that are now solved by inout (getting ranges/iterator from collection for instance).
