On Saturday, 23 February 2013 at 06:15:38 UTC, Jonathan M Davis
wrote:
Which then makes it so that the function can't be pure. While
overloading on
constness may be infrequently needed, we're definitely losing
something useful
if we can't do it anymore.
Note that is const is considered to be mutable or immutable and
do not mute immutable, then a mutable and immutable version of
the function can be conflated into a const one (and a different
entry in mutable/immutable objects).
This isn't much of a problem because mutable and immutable cannot
convert to each other anyway.
