On 28/12/13 09:06, Jakob Ovrum wrote:
[1] Which I'm not convinced of; e.g. `back` == `DateTime(2013, 1, 1) - dur!"days"(5)`.
Are you sure that's going to work if the iota covers a leap year? :-)
On 28/12/13 09:06, Jakob Ovrum wrote:
[1] Which I'm not convinced of; e.g. `back` == `DateTime(2013, 1, 1) - dur!"days"(5)`.
Are you sure that's going to work if the iota covers a leap year? :-)