On Saturday, 28 December 2013 at 14:13:08 UTC, Francesco Cattoglio wrote:
It's always the same "issue": you have to compute the last element inside iota, you should never rely on the user giving you ideal inputs.

Alright, so require division for bidirectionality when given a custom step. There's no reason division should be required for bidirectionality in the most common case of iota(start, end).

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