On Thu, 27 Mar 2014 00:35:38 -0400, deadalnix <[email protected]> wrote:
On Thursday, 27 March 2014 at 02:08:50 UTC, Steven Schveighoffer wrote:
On Wed, 26 Mar 2014 17:32:00 -0400, Nick Sabalausky
<[email protected]> wrote:
On 3/26/2014 7:44 AM, "Marc Schütz" <[email protected]>" wrote:
This is valid in both C and C++:
i, j = 0, 1;
It is equivalent to the following:
i;
j = 0;
1;
...
'=' has precedence over ','.
I think you get operator priority wrong and it will be (i), (j = 0),
(1). I added extra () to show how operator priority works.
I think that's what I said, no?
-Steve
