Nordlöw:
Ok, but this doesn't support multi-sorting, right?
If performance is not a top priority, you can use a tuple: r.schwartzSort!(x => tuple(x.a, x.b, x.c)); Bye, bearophile
bearophile via Digitalmars-d Wed, 05 Nov 2014 07:52:27 -0800
Nordlöw:
Ok, but this doesn't support multi-sorting, right?
If performance is not a top priority, you can use a tuple: r.schwartzSort!(x => tuple(x.a, x.b, x.c)); Bye, bearophile