On 12/9/14 9:23 AM, Nick Treleaven wrote:
On 08/12/2014 15:53, Steven Schveighoffer wrote:
scope ref int foo(ref int x);
will do it.
So:
int x;
foo(x) += 1;
will compile?
Yes, because foo's argument is not scope, it can be returned.
But I thought if you take a reference from the stack, it's inferred as
scope? I feel like there's a missing link somewhere if the scope is
missing from the parameter.
Will ref just automatically bind to any scoped reference?
What about this:
auto y = &x;
foo(*y) += 1;
-Steve
