On Monday, 29 December 2014 at 20:20:45 UTC, Steven Schveighoffer
wrote:
But this precludes doing anything with a mutable t inside foo,
since inout means "const within the function".
Hm, yes, this is indeed quite the problem. I have totally forgot
that compiler has no means of figuring out which invocation of
inout is currently used.
But something very similar feels necessary to me. There is
constness, lifetime, purity - inventing new dedicated keyword for
each case does not feel like scaling approach. Especially when
existing one is named so generic.
