Re: How is std.regex.replaceAllInto more efficient?

[Shriramana Sharma via Digitalmars-d]

Dmitry Olshansky wrote:

> No. Conceptually replace does replaceInto but creates a new appender
> each time. This is the overhead replaceInto means to avoid.

That's much clear now, thanks!

-- 
Shriramana Sharma, Penguin #395953