On 19.05.2016 08:04, Joakim wrote:
On Wednesday, 18 May 2016 at 17:10:25 UTC, Timon Gehr wrote:
It's not just slightly worse, it can cut the number of useful bits in
half or more! It is not unusual, I have actually run into those
problems in the past, and it can break an algorithm that is in Phobos
today!

I wouldn't call that broken.  Looking at the hex output by replacing %f
with %A in writefln, it appears the only differences in all those
results is the last byte in the significand.

Argh...

// ...

void main(){
    //double[] data=[1e16,1,-9e15];
    import std.range;
    double[] data=1e16~repeat(1.0,100000000).array~(-9e15);
    import std.stdio;
    writefln("%f",sum(data)); // baseline
    writefln("%f",kahan(data)); // kahan
    writefln("%f",kahanBroken(data)); // broken kahan
}


dmd -run kahanDemo.d
1000000000000000.000000
1000000100000000.000000
1000000000000000.000000

dmd -m32 -O -run kahanDemo.d
1000000000000000.000000
1000000000000000.000000
1000000000000000.000000


Better?

Obviously there is more structure in the data that I invent manually than in a real test case where it would go wrong. The problems carry over though.


As Don's talk pointed out,
all floating-point calculations will see loss of precision starting there.
...


This is implicitly assuming a development model where the programmer first writes down the computation as it would be correct in the real number system and then naively replaces every operation by the rounding equivalent and hopes for the best.

It is a useful rule if that is what you're doing. One might be doing something else. Consider the following paper for an example where the last bit in the significant actually carries useful information for many of the values used in the program.

http://www.jaist.ac.jp/~s1410018/papers/qd.pdf

In this case, not increasing precision gets the more accurate result,
but other examples could be constructed that _heavily_ favor increasing
precision.

Sure. In such cases, you should use higher precision. What is the problem? This is already supported (the compiler is not allowed to use lower precision than requested).

In fact, almost any real-world, non-toy calculation would
favor it.

In any case, nobody should depend on the precision out that far being
accurate or "reliable."


IEEE floating point has well-defined behaviour and there is absolutely nothing wrong with code that delivers more accurate results just because it is actually aware of the actual semantics of the operations being carried out.

Reply via email to