On Wednesday, 19 July 2017 at 14:56:58 UTC, Dukc wrote:
Shouldn't it be :
struct A
{
~this() shared {}
}
void main()
{
auto a = A();
shared b = A();
}
?
Because handling theard-local data as shared is safe as far as
I remember, but not the other way round.
Non-shared structs/classes can't call shared methods.
Unless you're saying that the above should work even though it
currently doesn't. Even then, I don't know about that. If your
type is complex enough to need a shared dtor then the dtor
probably needs to do some locking or extra checks. You don't want
to impose that cost on a struct instance which isn't shared.
