On Thursday, 16 November 2017 at 13:05:51 UTC, Petar Kirov
[ZombineDev] wrote:
On Wednesday, 15 November 2017 at 19:29:29 UTC, Steven
Schveighoffer wrote:
On 11/15/17 11:59 AM, Andrea Fontana wrote:
On Wednesday, 15 November 2017 at 15:25:06 UTC, Steven
Schveighoffer wrote:
alias foo = lambda1;
alias foo = lambda2;
What?
Yep. Would never have tried that in a million years before
seeing this thread :) But it does work. Tested with dmd
2.076.1 and 2.066. So it's been there a while.
-Steve
I guess you guys haven't been keeping up with language changes
:P
https://dlang.org/changelog/2.070.0.html#alias-funclit
And yes, you can use 'alias' to capture overload sets.
See also:
https://github.com/dlang/dmd/pull/1660/files
https://github.com/dlang/dmd/pull/2125/files#diff-51d0a1ca6214e6a916212fcbf93d7e40
https://github.com/dlang/dmd/pull/2417/files
https://github.com/dlang/dmd/pull/4826/files
https://github.com/dlang/dmd/pull/5162/files
https://github.com/dlang/dmd/pull/5202
https://github.com/dlang/phobos/pull/5818/files
Yes, as far as I understand this is just the normal way that you
add a symbol to an existing overload set, except now it also
interacts with the functionality of using an alias to create a
named function literal. Kind of interesting because I don't think
it was possible to do this before, e.g.:
int function(int) f1 = (int n) => n;
int function(int) f2 = (char c) => c;
Would obviously be rejected by the compiler. However, using the
alias syntax we can create an overload set from function
literals in addition to regular functions.
