Re: Calling nested function before declaration

[nkm1 via Digitalmars-d]

On Wednesday, 26 September 2018 at 22:46:21 UTC, Jonathan wrote:
This code fails to compile: ("undefined identifier fun")
void main() {
    fun();
    void fun() {}
}
Having the call after the declaration works:
void main() {
    void fun() {}
    fun();
}

Is this how it is intended to work?

It seems goofy that this works:
void main() {
    void fun2() {}
    void fun() {
         fun2()
    }
    fun();
}

But this fails to compile: ("undefined identifier fun2")
void main() {
    void fun() {
         fun2()
    }
    void fun2() {}
    fun();
}

What if I wanted this?
void main() {
    void fun2() {fun();}
    void fun() {fun2();}
    fun();
}

I can't see how the current behavior is at all better or to be 
preferred unless it is faster to compile?  What is the reason 
for it being how it is?

One of the reasons is consistency perhaps. Functions are not 
different from other identifiers:

void fun1()
{
    writeln(x);
}

int x = 1;

void fun2()
{
    writeln(y); // fails ("undefined indentifier y")
    int y = 2;
}