I just hate it when you have to write too much to get simple things done. Does this type have a member? Current approach:
1. import std.traits;
2. invoke hasMember!(S, "m")
Another approach:
1. I have the type, let's ask it: S::hasMember("m")
Map's thought to code.
My problem is that when you start using D's cool features you end up
with a really hard to understand and obscure code...
