On Tue, 21 Jun 2011 18:18:26 +0300, Michel Fortin
<[email protected]> wrote:
Actually, no copy is needed. Move takes the argument by ref so it can
obliterates it. Obliteration consists of replacing its bytes with those
in S.init. That way if you have a smart pointer, it gets returned
without having to update the reference count (since the source's content
has been destroyed). It was effectively be moved, not copied.
T move(ref T a) {
T b;
move(a, b);
return b;
}
T a;
whatever = move(a);
If T is a struct, i don't see how a copy is not needed looking at the
current state of move.
