> Since there are two inputs, we double that to be 40mW of power used up. > > 10*log10( P / 1mW ) > 10*log10( 40mW / 1 mW ) > 16.02 dBm
Ah, and at this point I encourage Aadil to ignore my response, as I was making a different (not very bright) assumption about why my numbers had come out a factor of two off (that the 2V was supposed to have been peak, not peak-to-peak). Sorry about that, and thanks Brian for getting the right answer out first. --Scott _______________________________________________ Discuss-gnuradio mailing list [email protected] http://lists.gnu.org/mailman/listinfo/discuss-gnuradio
