I'm afraid I dont understand. Are you saying I should be calculating:
P = (0.707V)^2/50 Ohms
P = 10mW
or
P = (0.707V)^2/200 Ohms
P = 2.5mW
The first one, 10mW, is what a signal source would be providing to the
BasicRX or LFRX input. So if you set your signal generator to 10 dBm,
you should see a signal at roughly full-scale.
The second one is the power that would be consumed at the input of the
ADC, but that is a completely meaningless number.
Matt
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