I think having the work fn return "-1" will cause the flowgraph to exit, so you
could potentially have a "self.count = 1" in __init__ and then when you've
output >= self.count, have work return -1
-Doug
Douglas Anderson | Intern
DOC/NTIA/ITS-T | 325 Broadway St., Boulder, CO 80305 | P: 303 497 3582
________________________________
From: discuss-gnuradio-bounces+danderson=its.bldrdoc....@gnu.org
[discuss-gnuradio-bounces+danderson=its.bldrdoc....@gnu.org] on behalf of
Thanasis Balafoutis [abalafou...@gmail.com]
Sent: Thursday, January 22, 2015 2:12 PM
To: discuss-gnuradio@gnu.org
Subject: [Discuss-gnuradio] Fwd: Write a source block in python
Hi
I wrote a simple source block that reads a string (as a parameter) and outputs
the corresponding array of bytes.
Here is the code:
class myblock(gr.sync_block):
def __init__(self, helloMsg):
gr.sync_block.__init__(self,
name="myblock",
in_sig=None,
out_sig=[numpy.byte])
self.helloMsg = helloMsg
def work(self, input_items, output_items):
out = output_items[0]
test = array.array('B',self.helloMsg)
for j in range(len(test)):
out[j] = test[j]
return len(output_items[0][:len(test)])
In the output I repeatedly get the helloMsg. (it seems that the work() function
is always running)
Is it possible to get in the output my helloMsg only one time (or a specific
amount of times) and then stop the execution of the flowgraph?
Thank you in advance!
Thanasis
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