Thank you Doug! return -1 indeed cause the flowgraph to exit. Is there any trick to stop also the execution on my program (after 1 sec)? Another problem I have is that the output is always 32768 bytes def work(self, input_items, output_items): ........ return len(output_items[0])
If I change it to this: return len(output_items[0][:len(test)]) my output becomes empty Is it possible to get in the output the exact number of bytes of my helloMsg parameter? 2015-01-22 23:31 GMT+02:00 Anderson, Douglas J. <[email protected]>: > I think having the work fn return "-1" will cause the flowgraph to exit, > so you could potentially have a "self.count = 1" in __init__ and then when > you've output >= self.count, have work return -1 > > -Doug > > *Douglas Anderson** | Intern* > DOC/NTIA/ITS-T | 325 Broadway St., Boulder, CO 80305 | P: 303 497 3582 > ------------------------------ > *From:* [email protected] > [[email protected]] on behalf of > Thanasis Balafoutis [[email protected]] > *Sent:* Thursday, January 22, 2015 2:12 PM > *To:* [email protected] > *Subject:* [Discuss-gnuradio] Fwd: Write a source block in python > > Hi > > I wrote a simple source block that reads a string (as a parameter) and > outputs the corresponding array of bytes. > Here is the code: > > class myblock(gr.sync_block): > > def __init__(self, helloMsg): > gr.sync_block.__init__(self, > name="myblock", > in_sig=None, > out_sig=[numpy.byte]) > self.helloMsg = helloMsg > > def work(self, input_items, output_items): > out = output_items[0] > > test = array.array('B',self.helloMsg) > for j in range(len(test)): > out[j] = test[j] > return len(output_items[0][:len(test)]) > > In the output I repeatedly get the helloMsg. (it seems that the work() > function is always running) > Is it possible to get in the output my helloMsg only one time (or a > specific amount of times) and then stop the execution of the flowgraph? > > Thank you in advance! > Thanasis > >
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