Yeh, I got that, but when you try to use a jquery object twice in a
chain it doens't work...
$('div').each(
$('div').find('img').hide();
$('div').find('img').show();
);
Wouldn't it just be easier to pass back the this (instead of changing in
the jquery object itself)?
Jörn Zaefferer wrote:
> Abdur-Rahman Advany schrieb:
>
>> Hi guys,
>>
>> I am trying to figure out how jQuery works internally. There is a stack
>> maintained within jQuery but why does jQuery change the 'this' array of
>> objects? why not just pass back the modified array when using things
>> like find?
>>
>>
> The stack allows to revert to older states. Check the documentation for
> end(), that explains it better.
>
> -- Jörn
>
>> Abdul
>>
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>>
>>
>
>
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