Hi,
> Controller set of methods is returned..
>
> $('#grid').grid().data(data).drig().show()
> $('#grid').grid().scrollToRow(6).drig().css("border", "1px")
>
> A controller object is returned..
>
> var grid = null
> $("grid").grid({
> data: data,
> onComplete: function(controller) { grid = controller }
> })
> grid.srollToRow(6)
>
> What is best practice?
How about the Idea to have a jQuery-function that returns the controller
object:
$('#grid').grid({data:data}).show().gridController().scrollToRow(6);
That way the function that creates the grid does not break the chain, but
there is a function that returns a controller object. You don't necessarily
need a way to come back to jQuery if you do it that way, because you can
chose to get the controller Object later in the queue.
You should think if you want a controller object that can handle mutliple
grids at the same time:
$('.allmygrids').grid({data:data}).show().gridController().scrollToRow(6);
If not, then gridController() needs to take a parameter to know which of the
grids you mean:
$('.allmygrids').grid({data:data}).show().gridController(42).scrollToRow(6);
Christof
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