Karl Swedberg schrieb:
> You might also be able to reduce this a bit, depending on your markup:
>
> $('a.selected').parents('div.linkSubMenu').show();
>
> It seems a shame to traverse all the way down that set of nodes, only to
> have to traverse back up.
What about some XPath magic:
$("//div.linkSubMenu[ul/li/a.selected]")
At least its in the documentation, but I've not used it so far.
http://docs.jquery.com/DOM/Traversing/Selectors#XPath_Selectors
Look for "Nodelist".
-- Klaus
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