Dave,
This is the default behavior for all Java servers/daemons. If you only want
to launch a server for a limited time, you can do something like:
Server connector = new Server(Protocol.HTTP, 8182, null);
System.out.print("Starting connector... ");
connector.start();
System.out.println("done");
System.out.print("Waiting " + waitTime + " ms...");
Thread.sleep(waitTime);
System.out.println("done");
System.out.print("Stopping connector... ");
connector.stop();
System.out.println("done");
Best regards,
Jerome
> -----Message d'origine-----
> De : Dave Pawson [mailto:[EMAIL PROTECTED]
> Envoyé : mercredi 20 décembre 2006 11:34
> À : [email protected]
> Objet : Re: Tutorial, cleanup
>
> On 20/12/06, Jerome Louvel <[EMAIL PROTECTED]> wrote:
> >
> >
> >
> > Hi Dave,
> >
> > I assume that you are running this from an IDE, otherwise
> a CTRL-c would kill it.
>
> Yes, netBeans.
> I'd prefer a programmatic method though?
>
>
> // Create the HTTP server and listen on port 8182
> Server srv = new Server(Protocol.HTTP, 8182, restlet);
> try {
> srv.start();
> } catch (Exception ex) {
> ex.printStackTrace();
> }
> try {
> srv.stop();
> } catch (Exception ex) {
> ex.printStackTrace();
> }
>
>
> I'm trying to think of a new user wondering what is happening?
> Runs the first time, then produces an error the second time.
>
> regards
>
>
>
>
>
> --
> Dave Pawson
> XSLT XSL-FO FAQ.
> http://www.dpawson.co.uk
