Thanks guys. That was exactly the problem.

On Sun, Mar 29, 2009 at 10:40 AM, Darin Kohles <[email protected]> wrote:
> to be safe (assuming you don't nest)
>
> channels..channel[...@name
>
> its the '.@' that is missing in your code:
>
> you can also do...
>
> myXMLroot..(@name == "bob") ; // doesn't matter how nested the node with
> "bob" as an attribute is.
>
> On Sun, Mar 29, 2009 at 8:16 AM, Justin Nichols <[email protected]>
> wrote:
>>
>> See if this helps:
>>
>> var xml:XML =
>>        <rootTag>
>>                <channel name="a"/>
>>                <channel name="b"/>
>>                <channel name="c"/>
>>        </rootTag>;
>>
>> var list:XMLList = xml.channel;
>>
>> var firstChannelName:String = list[...@name;  // may need to toString() or
>> cast as String
>>
>> Thanks,
>>
>> Justin Nichols
>>
>>
>> On Mar 29, 2009, at 8:08 AM, Atlanta Geek wrote:
>>
>>> So I have an XMLList  (named channels) that looks like this in xml
>>>
>>> <channel name="a"/>
>>> <channel name="b"/>
>>> <channel name="c"/>
>>>
>>> It is the data source for a combobox that is an item editor in a
>>> datagrid.
>>>
>>> So how do I access the name attribute of the second channel.
>>> channels[1].name  does not give me the name value. Any suggestions?
>>>
>>> --
>>> http://www.atlantageek.com
>>>
>>>
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>>
>>
>>
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>
>
>
> --
> Darin Kohles
> RIA Developer
>



-- 
http://www.atlantageek.com


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